(x+7)^2=(x+7)(3x+4)

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Solution for (x+7)^2=(x+7)(3x+4) equation: 



(x+7)^2=(x+7)(3x+4)

We move all terms to the left:

(x+7)^2-((x+7)(3x+4))=0

We multiply parentheses ..

-((+3x^2+4x+21x+28))+(x+7)^2=0



We calculate terms in parentheses: -((+3x^2+4x+21x+28)), so:

(+3x^2+4x+21x+28)

We get rid of parentheses

3x^2+4x+21x+28

We add all the numbers together, and all the variables

3x^2+25x+28

Back to the equation:

-(3x^2+25x+28)



We get rid of parentheses

-3x^2-25x+(x+7)^2-28=0

We move all terms containing x to the left, all other terms to the right

-3x^2-25x+(x+7)^2=28

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